How many different necklaces are there with six beads and three Colours where we allow both rotations and flips?

How many necklaces can you make with 6 beads of 3 colors?

The first step is easy: the number of ways to colour 6 beads, where each bead can be red, green or blue, is 36 = 729. Next we put the beads on a necklace, and account for duplicate patterns.

How many arrangements of beads are possible in a bracelet if there are 6 different designs of beads?

Since there are 6! linear arrangements of six distinct beads, the number of distinguishable circular arrangements is 6! 6=5!

How many ways of making a necklace is possible with 7 beads of different Colour?

= 5040 diffrent necklaces.

How many unique ways can 5 beads of different Colours be strung to form a necklace?

One is clockwise, another is anticlockwise. Here in both directions we will get the same arrangement. So, we have to divide 24 by 2. Therefore the total number of different ways of arranging 5 beads is 242=12 .

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How many necklaces can be formed with 6 white and 5 red beads if each necklace is unique how many can be formed?

5! but correct answer is 21.

How many ways can 10 different colored beads be threaded on a string?

Answer: This is called a cyclic permutation. The formula for this is simply (n-1)!/2, since all the beads are identical. Hence, the answer is 9!/2 = 362880/2 = 181440.

How many different bangles can be formed from 8 different colored beads?

How many different bangles can be formed from 8 different colored beads? Answer: 5,040 bangles .

How many ways can you make a bracelet with 5 different beads?

Thus for n=5, there are possible 4!/2=12 different bracelets.

How many necklaces are in 8 beads?

The number of ways in which 8 different beads be strung on a necklace is. 2500. 2520.

How many ways 8 different beads can be arranged to form a necklace?

2520 Ways 8 beads of different colours be strung as a necklace if can be wear from both side.

How many necklaces of 12 beads each can be made from 18 beads of various Colours?

Correct Option: C

First, we can select 12 beads out of 18 beads in 18C12 ways. Now, these 12 beads can make a necklace in 11! / 2 ways as clockwise and anti-clockwise arrangements are same. So, required number of ways = [ 18C12 . 11! ] / 2!